#include<bits/stdc++.h>
using namespace std;
int main(){
int n, sum = 8;
char c;
cin >> n >> c;
if(n > 1000){
if((n-1000)%500 > 0){
sum += 4;
}
sum += (n-1000)/500*4;
} if(c == ...
| English Article | Word Count | Duration | Accuracy | Speed | Backspace | Error | Slogan |
|---|---|---|---|---|---|---|---|
| 《代码1》 | 249字 | 1.0分钟 | 100% | 72 CPM | 6 次 | 0 | 不及格，加强练习！ |
| Inspirational quotes: 独创常常在于发现两个或两人以上研究对象或设想之间的联系或相似之点。 ——贝弗里奇 | |||||||
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