#include<cstdio>
typedef long long LL;
void exgcd(LL a,LL b,LL &x,LL &y,LL &d)
{
if(b==0) d=a,x=1,y=0;
else exgcd(b,a%b,x,y,d),t=x,x=y,y=t-a/b*y;
}
LL inv(LL t, LL p)
{
LL d, x, y;
e...
| English Article | Word Count | Duration | Accuracy | Speed | Backspace | Error | Slogan |
|---|---|---|---|---|---|---|---|
| 《费马小定理求逆元-模板》 | 599字 | 2.3分钟 | 100% | 210 CPM | 52 次 | 2 | 良好，向更快挑战！ |
| The wrong word this time: ;,} | |||||||
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Suggestion:
可能对按键不够熟悉，或者对输入法不够熟练所导致，不要急慢慢来，先打对把准确率提高，然后逐渐的加快速度，最后才能打准打快。
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