#include<bits/stdc++.h>
using namespace std;
int main()
{
int a=3,b=6,c=9,d=5;
cin>>a>>b>>c;
if(a>3)
cout<<char(a*b-(c+a-d)+(b*d));
else
cout<<b-d;
return 0;
}ssssssssssssss...
English Article | Word Count | Duration | Accuracy | Speed | Backspace | Error | Slogan |
---|---|---|---|---|---|---|---|
《c++(1) 7/2》 | 200字 | 45.0分钟 | 100% | 74 CPM | 0 次 | 0 | 不及格,加强练习! |
Inspirational quotes: 任何问题都有解决的办法,无法可想的事是没有的。 ——爱迪生 | |||||||
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