const int N = 2e5 + 10;
int n, d, k;
typedef pair<int, int> PII;
#define x first
#define y second
PII a[N];
int cnt[N];
bool b[N];
int main()
{
cin >> n >> d >> k;
for (int i = 1; i <= n; i ++...
| English Article | Word Count | Duration | Accuracy | Speed | Backspace | Error | Slogan |
|---|---|---|---|---|---|---|---|
| 《1》 | 699字 | 2.6分钟 | 100% | 40 CPM | 19 次 | 0 | 不及格，加强练习！ |
|
Suggestion:
总的来说速度上可能不是很快，多练习键位、或英文文章巩固一下，然后试着对应的输入法练习上，多增加词组等、一次性多字的输出，这样可以总体上提高部份速度。
|
|||||||
| Inspirational quotes: 将事而能弭，遇事而能捄，既事而能挽，此之谓达权，此之谓才，未事而知其来，始事而要其终，定事而要其变，此之谓长虑，此之谓识。 ——曾国藩 | |||||||
| What do you think of this article? Give it a rating and let it serve as a guiding light for others | |||||||
Registration with the Ministry of Industry and Information Technology: Min ICP No. 19000005