// Calculate C(n, m) % p
#include <bits/stdc++.h>
typedef long long ll;
ll C(ll n, ll m, ll p) {
}
ll Lucas(ll n, ll m, ll p) {
if(m == 0) return 1;
return (C(n % p, m % p, p) * Lucas(n / p, m / p, ...
| English Article | Word Count | Duration | Accuracy | Speed | Backspace | Error | Slogan |
|---|---|---|---|---|---|---|---|
| 《[c++] Lucas定理》 | 307字 | 1.6分钟 | 100% | 182 CPM | 40 次 | 0 | 良好，向更快挑战！ |
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Suggestion:
可能对按键不够熟悉，或者对输入法不够熟练所导致，不要急慢慢来，先打对把准确率提高，然后逐渐的加快速度，最后才能打准打快。
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