#include <iostream>
using ll = long long;
const ll MOD = 1e9 + 7;
ll qpow(ll a, ll n){
if(n == 0) return 1;
ll res = qpow(a, n / 2); res *= res; res %= MOD;
if(n & 1) res *= a;
return res % MOD;
}
int...
English Article | Word Count | Duration | Accuracy | Speed | Backspace | Error | Slogan |
---|---|---|---|---|---|---|---|
《[c++] 快速幂(递归)》 | 278字 | 2.0分钟 | 100% | 206 CPM | 41 次 | 0 | 良好,向更快挑战! |
Suggestion:
可能对按键不够熟悉,或者对输入法不够熟练所导致,不要急慢慢来,先打对把准确率提高,然后逐渐的加快速度,最后才能打准打快。
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Inspirational quotes: 须有宁拙毋巧之意,而后可以持久。 ——曾国藩 | |||||||
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